Question

Using bisection method find the second iteration of the root of x2-5=0 between 2 and 3?

Answer 1

Given:

An equation is provided $x^2-5=0$

To Find:

Root of equation by bisection method?

Step-by-step explanation:

first iteration-

f(x)=$x^2-5=0$

f(2)=-1

f(3)=4

Now for second iteration

$\frac{x_1+x_2}{2}=\frac{2+3}{2} =\frac{5}{2}$

  $f(\frac{5}{2} )=\frac{5}{4}$

Now $f(2)\times f(\frac{5}{2} )<0$

Thus interval will be(2,5/2)