Math, asked by adrijabanerjee59, 8 months ago

Using bisection method the root e^x-3x=0,correct to two decimal places,which like between 1 and 2 is A)1.51 B)1.52 C)1.6 D)1.55

Answers

Answered by taran1659
3

Answer:

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Answered by NamrataSachdeva
2

Answer:

Using bisection method, the root of e^x-3x=0,correct to two decimal places,between 1 and 2 is 1.51.

Option (A) 1.51 is the right answer.

Step-by-step explanation:

  • Numerical methods in mathematics use numerical approximations for solving complex mathematical problems that usually has no analytical solution.
  • They follow algorithms (series of steps) to arrive at a solution.

There are several types of numerical methods such as:

  1. Euler method
  2. Trapezoidal law
  3. Range - Kutta methods
  4. Newton method

What is Bisection method?

Bisection method is the most straight forward numerical method to solve a polynomial equation or a continuous function.

Method:

  1. Initially by trial and error method, find two numbers (a,b) such that the function is positive at one number (b) and negative at the other (a).
  2. Then calculate the average of the two numbers (m = (a+b)/2).
  3. Repeat the first step with two numbers and the average.
  4. If the function value is positive at m and negative at a then the new set of numbers become (a,m).
  5. If the function value is negative at m and positive at b then the new set of numbers become (m,b).
  6. If the function value is zero at m, them m is the root of the equation or function.
  7. Repeat this procedure until the function value approaches zero.

Calculation:

Given equation is f(x) =  e^{x} -3x = 0

And the interval is [1,2]

f(1) = e - 3 = 2.718 - 3 = -0.282

f(2) = e^{2} - 6 = 1.389

Since f(1) is negative and f(2) is positive, there exists a root in this interval.

m = average of 1,2 = (1 + 2) / 2 = 1.5

f(1.5) = e^{1.5} -3*1.5 = -0.0183

Since f(1.5) is negative and f(2) is positive, there exists a root in this interval.

m = average of 1.5, 2 = (1.5+2)/2 = 1.75

f(1.75) = e^{1.75} -3*1.75 = 0.504

Since f(1.5) is negative and f(1.75) is positive, there exists a root in this interval.

m = average of 1.5,1.75 = (1.5 + 1.75) / 2 = 1.625

f(1.625) = e^{1.625} -3*1.625 = 0.203

Since f(1.5) is negative and f(1.625) is positive, there exists a root in this interval.

f(1.56) = e^{1.56} -3*1.56 = 0.083

Since f(1.5) is negative and f(1.56) is positive, there exists a root in this interval.

m = average of 1.5,1.56 = (1.5+1.56)/2 = 1.53

f(1.53) = e^{1.53} -3*1.53 = 0.03

Since f(1.5) is negative and f(1.53) is positive, there exists a root in this interval.

m = average of 1.5,1.53 = (1.5+1.53)/2 = 1.506

f(1.506) = e^{1.506} -3*1.506 = -0.008

Since f(1.506) is negative and f(1.53) is positive, there exists a root in this interval.

m = average of 1.506,1.53 = (1.506+1.53)/2 = 1.518

f(1.518) = e^{1.518} -3*1.518 = 0.009

Since f(1.506) is negative and f(1.518) is positive, there exists a root in this interval.

m = average of 1.506,1.518 = (1.506+1.518)/2 = 1.512

f(1.512) = e^{1.512} -3*1.512 = -0.0002

Since f(1.512) is negative and f(1.518) is positive, there exists a root in this interval.

Therefore the root of e^{x} -3x = 0 between 1 and 2 correct to two decimal places is 1.51.

Option (A) 1.51 is the right answer.

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