Using bisection method the root e^x-3x=0,correct to two decimal places,which like between 1 and 2 is A)1.51 B)1.52 C)1.6 D)1.55
Answers
Answer:
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Answer:
Using bisection method, the root of e^x-3x=0,correct to two decimal places,between 1 and 2 is 1.51.
Option (A) 1.51 is the right answer.
Step-by-step explanation:
- Numerical methods in mathematics use numerical approximations for solving complex mathematical problems that usually has no analytical solution.
- They follow algorithms (series of steps) to arrive at a solution.
There are several types of numerical methods such as:
- Euler method
- Trapezoidal law
- Range - Kutta methods
- Newton method
What is Bisection method?
Bisection method is the most straight forward numerical method to solve a polynomial equation or a continuous function.
Method:
- Initially by trial and error method, find two numbers (a,b) such that the function is positive at one number (b) and negative at the other (a).
- Then calculate the average of the two numbers (m = (a+b)/2).
- Repeat the first step with two numbers and the average.
- If the function value is positive at m and negative at a then the new set of numbers become (a,m).
- If the function value is negative at m and positive at b then the new set of numbers become (m,b).
- If the function value is zero at m, them m is the root of the equation or function.
- Repeat this procedure until the function value approaches zero.
Calculation:
Given equation is f(x) =
And the interval is [1,2]
f(1) = e - 3 = 2.718 - 3 = -0.282
f(2) = = 1.389
Since f(1) is negative and f(2) is positive, there exists a root in this interval.
m = average of 1,2 = (1 + 2) / 2 = 1.5
f(1.5) =
Since f(1.5) is negative and f(2) is positive, there exists a root in this interval.
m = average of 1.5, 2 = (1.5+2)/2 = 1.75
f(1.75) =
Since f(1.5) is negative and f(1.75) is positive, there exists a root in this interval.
m = average of 1.5,1.75 = (1.5 + 1.75) / 2 = 1.625
f(1.625) =
Since f(1.5) is negative and f(1.625) is positive, there exists a root in this interval.
f(1.56) =
Since f(1.5) is negative and f(1.56) is positive, there exists a root in this interval.
m = average of 1.5,1.56 = (1.5+1.56)/2 = 1.53
f(1.53) =
Since f(1.5) is negative and f(1.53) is positive, there exists a root in this interval.
m = average of 1.5,1.53 = (1.5+1.53)/2 = 1.506
f(1.506) =
Since f(1.506) is negative and f(1.53) is positive, there exists a root in this interval.
m = average of 1.506,1.53 = (1.506+1.53)/2 = 1.518
f(1.518) =
Since f(1.506) is negative and f(1.518) is positive, there exists a root in this interval.
m = average of 1.506,1.518 = (1.506+1.518)/2 = 1.512
f(1.512) =
Since f(1.512) is negative and f(1.518) is positive, there exists a root in this interval.
Therefore the root of between 1 and 2 correct to two decimal places is 1.51.
Option (A) 1.51 is the right answer.
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