Question

Using -Bohr’s atomic model, derive an equation for radius of orbit of an electron.

Answer 1

I hope it helps please mark as brainlist

Answer 2

according to Bohr's theory ,

nh/2π = mvr ........(1)

and KZe²/r² = mv²/r ......(2)

now, from equation (1)

nh/2π = mvr

v = nh/2πmr

put this in equation (2)

⇒KZe²/r² = m{ nh/2mπr}²/r

⇒KZe²/r² =m.n²h²/4π²m²r³

⇒KZe²/r² = n²h²/4π²mr³

⇒KZe²/r² =n²h²/4π²mr³

⇒r = n²h²/4π²mKZe²

here

• r is the radius of nth orbit .
• h is plank's constant
• m is mass of electrons
• K is kappa's constant
• e = charge of electron

putting values of h, m, K , e , in SI system

we get, r = (0.529)n²/Z A°