Question

using Bohr's equation calculate the distance travelled by an electron of hydrogen atom when it jumps from 1st to 2nd orbit​

Answer 1

Answer:

• _n1=1
• n_2=2

We know

$\boxed{\sf Distance=\dfrac{(n_2-n_1)(n_2-n_1+1)}{2}}$

$\\ \sf\longmapsto Distance=\dfrac{(2-1)(2-1+1)}{2}$

$\\ \sf\longmapsto Distance=\dfrac{1(2)}{2}$

$\\ \sf\longmapsto Distance=\dfrac{2}{2}$

$\\ \sf\longmapsto Distance=1nm$