Using Bohr' theory of atomic structure drive the expression of hydrogen atom
Answers
Answer:
Let e, m and v be respectively the charge, mass and velocity of the electron and r the radius of the orbit. The positive charge on the nucleus is Ze, where Z is the atomic number (in case of hydrogen atom Z = 1). As the centripetal force is provided by the electrostatic force of attraction. We have
r
mv
2
=
4πε
0
1
r
2
(Ze)×e
mv
2
=
4πε
0
r
Ze
2
....(i)
From the first postulate, the angular momentum of the electron is
mvr=n
2π
h
....(ii)
where n (= 1, 2, 3, ...) is quantum number. Squaring eq. (ii) and dividing by eq. (i), we
get
r=n
2
πmZe
2
h
2
ε
0
Z=1
Since
r=n
2
πme
2
h
2
ε
0
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Answer:
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Explanation:
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