Using Boolean logic solve this XYZ' + X'Y'Z
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The Axioms of (Any) Boolean Algebra ... We will use the first non-trivial Boolean Algebra: A = {0,1}. ... X · (Y · Z)=(X · Y) · Z ... (X + Y + Z)(X + YZ) = XX + XYZ + YX + Y YZ + ZX + ZYZ ... The minterm solution: cover each 1 .
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