Question

using cluitable identity find the value
(i)(106)²
(ii)(99)²
(iii(110)²
(iv)(102)²-(98)²
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Answer 1

Answer:

1) [106]^2 = [100 + 6]^2

= [10000 + 36 + 1200]

= 11236

2) [99]^2 = [100 - 1]^2

= [10000 + 1 - 200]

= 9801

3) [110]^2 = [100 + 10]^2

= [10000 + 100 + 2000]

= 12100

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Answer 2

Answer:

i ) 11236

ii ) 9801

iii )2100

I've) 2440

Step-by-step explanation:

i : 106 × 106

= 11236

ii : 99 × 99

= 9801

iii : 110 × 110

= 2100

iv : ( 102 × 102 ) - ( 98 × 98 )

= 10404 - 7964

= 2440