Question

Using completing the square method show that the equation
X^2-8x+18=0
Has no solution

Answer 1

Answer:

since the roots are not real , the given equation has no solutio

Step-by-step explanation:

$x^2-8x+18=0\\\\x^2-8x=-18$

To make L.H.S a perfect square, add 16 to both sides

$X^2-8x+16=-18+16\\\\(x-4)^2=-2\\\\x-4=\sqrt{-2}\:or\:x-4=-\sqrt{-2}\\\\x=4+\sqrt{-2}\:or\:x=4-\sqrt{-2}$,which are not real numbers

Hence the given equation has no solution.

Answer 2

Step-by-step explanation:

X² - 8x + 18 = 0

X² - 8x = -18

X² - 8x + 16 = -18 + 16

( X - 4 )² = -2

Since √D < 0

Thus there are no real roots, and hence the equation has no solution .