Question

using completing the square method to solve correct to 2 decimal points 3y^2-5y+2=0
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Answer 1

Answer:

$y = 1 \: \: \: or \: \: \: y = \frac{2}{3}$

Step-by-step explanation:

$3 {y}^{2} - 5y + 2 = 0 \\ {y}^{2} - \frac{5}{3} y + \frac{2}{3} = 0 \: \: \: \: \: on\: dividing \: throughout \: by \: 3 \\ \\ \\ \\ add \: \: \: \frac{25}{36 \: \: } \: to \: both \: sides \: \\ \\ ({y}^{2} - \frac{5}{3} y + \frac{25}{36} ) + \frac{2}{3} = \frac{25}{36} \\ {(y - \frac{5}{6} )}^{2} = \frac{25}{36} - \frac{2}{3} \\ \\ {(y - \frac{5}{6} )}^{2} = \frac{25 - 24}{36} \\ \\ {(y - \frac{5}{6} )}^{2} = \frac{1}{36} \\ \\ y - \frac{5}{6} = \frac{1}{6} \: \: \: \: \: \: \: or \: \: \: \: \: \: \: y - \frac{5}{6} = - \frac{1}{6} \\ \\ \\ \\ y = 1 \: \: \: or \: \: \: y = \frac{2}{3}$