using complex number find i^23
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Answer:
-i = -√-1
Step-by-step explanation:
We know that i = √-1
So, i^2 = -1
So, i^4 = (i^2)^2 = (-1)^2 = 1
i^23 = i^20*i^3 = (i^4)^5 * (i^2)i = 1*(-1)i = -i*1 = -i = -√-1
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