Question

using converse of BPT prove that the line joining the mid points of any two sides is parallel to the third side.​

Answer 1

Answer:

Given:

ΔABC in which D and E are the mid points of AB and AC respectively such that AD=BD and AE=EC.

To Prove: DE || BC

Proof: D is the mid point of AB (Given)

∴ AD=DB

⇒ AD/BD = 1 … (i)

Also, E is the mid-point of AC (Given)

∴ AE=EC

⇒AE/EC = 1 [From equation (i)]

From equation (i) and (ii), we get

AD/BD = AE/EC

∴ DE || BC [By converse of Basic Proportionality Theorem]

Hence , the line joining the mid points of any two sides of a triangle is parallel to the third side....

hence prove

Answer 2

Answer:

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