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Using converse of thales theorem,prove that the line joining the mid points of any two sides of a triangle is parallel to the third side

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Answered by Anonymous
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\bf\huge\underline{Question}

Using converse of thales theorem,prove that the line joining the mid points of any two sides of a triangle is parallel to the third side

\bf\huge\underline{Answer}

We have ∆ABC in which D and E are the mid-points of sides AB and AC respectively.

Therefore, AD = DB ⠀⠀⠀⠀⠀⠀⠀⠀⠀.....(1)

and AE = EC ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ .....(2)

From (1) and (2), we have

\dfrac{AD}{DB} = 1 and \dfrac{AE}{EC} = 1

=> \dfrac{AD}{DB} = \dfrac{AE}{EC}

=> DE || BC (By converse of Basic proportionality theorem).

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