Question

Using cramers rule, solve the following equations
2/x+3/y=2
5/x+8/y=31/6​

Answer 1

Answer:

Step-by-step explanation:

Systems of Equations - Three Variables

Objective: Solve systems of equations with three variables using addition/elimination.

Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down

to one with only one variable (by substitution or addition). With three variables

we will reduce the system down to one with two variables (usually by addition),

which we can then solve by either addition or substitution.

To reduce from three variables down to two it is very important to keep the work

organized. We will use addition with two equations to eliminate one variable.

This new equation we will call (A). Then we will use a different pair of equations

and use addition to eliminate the same variable. This second new equation we

will call (B). Once we have done this we will have two equations (A) and (B)

with the same two variables that we can solve using either method. This is shown

in the following examples.

Example 1.

3x +2y − z = − 1

− 2x − 2y +3z = 5 We will eliminate y using two different pairs of equations

5x +2y − z = 3

1

3x +2y − z = − 1 Using the first two equations,

− 2x − 2y +3z = 5 Add the first two equations

(A) x +2z = 4 This is equation (A), our first equation

− 2x − 2y +3z = 5 Using the second two equations

5x +2y − z = 3 Add the second two equations

(B) 3x +2z = 8 This is equation (B), our second equation

(A) x +2z = 4 Using (A) and (B) we will solve this system.

(B) 3x +2z = 8 We will solve by addition

− 1(x +2z) =(4)( − 1) Multiply (A) by − 1

− x − 2z = − 4

− x − 2z = − 4 Add to the second equation, unchanged

3x +2z = 8

2x = 4 Solve, divide by 2

2 2

x = 2 We now have x! Plug this into either(A) or(B)

(2) +2z = 4 We plug it into (A),solve this equation,subtract 2

− 2 − 2

2z = 2 Divide by 2

2 2

z = 1 We now have z! Plug this and x into any original equation

3(2) +2y − (1)= − 1 We use the first, multiply 3(2) =6 and combine with − 1

2y + 5= − 1 Solve,subtract 5

− 5 − 5

2y = − 6 Divide by 2

2 2

y = − 3 We now have y!

(2, − 3, 1) Our Solution

Answer 2

Answer:

Step-by-step explanation: