Question

Using cube root table, find the cube root of 953

Answer 1

Here is your answer

We have,

950<953<960

$= > \sqrt[3]{950} < \sqrt[3]{953} < \sqrt[3]{960}$

From the cube root table, we have

$\sqrt[ 3]{950} = 9.830 \: \: and \: \sqrt[3]{960} = 9.865$

Thus, for the difference of ( 960 - 950 ) i.e 10, The difference in the values
= ( 9.865 - 9.830 ) = 0.035

: For the difference of ( 935 - 950 ) i.e 3, the difference in the values

$= ( \frac{0.035}{10} \times 3) \\ \\ = 0.0105 = 0.010 \: \: ( \: upto \: \: three \: \: decimal \: \: places \: \: )$

$Hence \: \: \sqrt[3]{953} = 9.830 + 0.010 = 9.840$


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