Question

Using determinant find area of triangle with vertices (1,-1), (2, 4), (-3, 5)​

Answer 1

area of triangle,

=1/2{1(3+3) -4(2+5) +1(-6+15) }

=1/2(6-28+9)

=1/2(-13)

-13/2 is not equal to zero

so, the area of triangle

=-13/2square.units

these points are not collinear because area of triangle is not equal to zero

hope it helps

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