Question

Using determinant find the area of triangle with vertices A(1, 5) ,B(3, -8) and C(0, 1)​

Answer 1

A (1,5)

B (3,-8)

C (0,1)

step by step explanation:

we know that

Area of triangle by determinant=

$\frac{1}{2} |(( 1 \times ( - 8))- (3 \times 5)) +( (3 \times 1) -(0 \times ( - 8))) + ((0 \times 5) - (1 \times 1)) |$

$= \frac{1}{2} |(8 - 15) + (3 - 0) + (0 - 1)|$

$= \frac{1}{2} | - 7 + 3 - 1|$

$= \frac{1}{2} | - 6|$

$= \frac{1}{2} 6$

$= 3$