Using diffrential , find the approximation value of √49.5 upto 3 places of decimal.
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Hi !
Solution :- √49.5
consider f(x) = √x => f'(X) = 1/2•x
let , X = 49 and ∆x ,= 0.5
now, f(x+∆x) ,=f(x) + ∆xf'(X)
°•° √x+∆x = √x+1/2√x ∆x
=> √49.5 = √49+0.5/√2√49= 7+05/140
= 7+0.036
=>√49.5=7.036
Hope it's helpful
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