Question

Using dimension , show that 1 joule = 10 raised to 7 erg

Answer 1

1J = Nm

= 10^5 dyne x 100 cm

=10^5+2

=10^7 erg

Answer 2

force dimension is M^1L^2T^-2

so n2 = n1 (1kg/1g)^1*(1m/1cm)^2*(1s/1s)^-2

so n2= 10^3*10^4*1

n2 =10^7erg

1 joule = 10^7erg