using distance formula:A (-3,2) B(1,-2) C(9,-10) but in explation
Answers
Step-by-step explanation:
given,
given, A(-3,2) ,B(1,-2) ,C(9,-10)
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64 =√128
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64 =√128 distance between A and C=√(9+3)^2+(-10-2)^2
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64 =√128 distance between A and C=√(9+3)^2+(-10-2)^2 =√144+144
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64 =√128 distance between A and C=√(9+3)^2+(-10-2)^2 =√144+144 =√288
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64 =√128 distance between A and C=√(9+3)^2+(-10-2)^2 =√144+144 =√288therefore,AB+BC=AC
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64 =√128 distance between A and C=√(9+3)^2+(-10-2)^2 =√144+144 =√288therefore,AB+BC=AC √32+√128=√288
given, A(-3,2) ,B(1,-2) ,C(9,-10) distance between A and B=√(1+3)^2+(-2-2)^2 =√16+16 =√32 distance between B and C=√(9-1)^2+(-10+2)^2 =√64+64 =√128 distance between A and C=√(9+3)^2+(-10-2)^2 =√144+144 =√288therefore,AB+BC=AC √32+√128=√288 SINCE AB+BC is not equal to AC
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