Question

Using distance formula, show that (3, 3) is the centre of the circle passing through the points (6, 2), (0, 4) and (4, 6).
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Answer 1

Answer:

yes

Step-by-step explanation:

Radius = √10 unit  , Equation of circle : (x - 3)² + (y - 3)² = 10 or x² + y² - 6x - 6y + 8 = 0

Step-by-step explanation:

(3 , 3) is center of circle

& Circle passes through (6,2),(0,2) and (4,6)

=>radius ² =  ( 6 - 3)² + (2 - 3)²  = (0 - 3)² + (2 - 3)² = (4 - 3)² + (6 - 3)²

=>radius ² = 9 + 1   = 9 + 1 = 1 + 9

=> radius ² = 10

=> Radius = √10

Equation of circle

(x - 3)² + (y - 3)² = 10

=> x² - 6x + 9 + y² - 6y + 9 = 10

=> x² + y² - 6x - 6y + 8 = 0

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