Using distance formula, show that the points A( -6, 0) , B( 0, 5) and C( 6, 10) are collinear.
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A(-6,0) b(0,5) and c(6,10)
A(-6,0) b (0,5) (a= x1,y1 b=X2,y2)
distance formula AB =√(x2-x1)²+ (y2-y1)²
AB=√[0-(-6)]+ (5-0)²
=√(0+6)²+(5)²
=√(6)²+(5)²
=√36+25
= √61
b(0,5) and c(6,10)
BC =√ (6-0)²+(0-5)²
=√(6)²+(-5)²
=√36+25
√61
c(6,10) a(-6,0)
CA = √(-6-6)²+(0-10)²
=√(0)²+(-10)²
=√100²
therefore ab=bc is not equal to CA
these points are not collinear
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