Question

using divisibility rules check whether the following numbers
are divisible by 3, 4, 5 ,9 and 11
a)30451
b)2547
c)5648
d)10674​

Answer 1

Step-by-step explanation:

rule is

divisible by 3= add all the no.

as example- questions no.1 - 3+0+4+5+1= 13 it's no divisible by 3

divisible by 4 - last two digits are divided

as for ex. question a - 51/4 = 12.35 is not divisible by 4

question no.c- 48/4 = 12 it's divisible by 4

divisible by 5 = last digits of 5,0 it's divisible

I hope this will help u

Answer 2

_________divisibility of 3 .., = all no. when added should be multiple of 3

––– 30451 = 3+0+4+5+1 = 13 ..., so .., 30451 is not divisible by 3

––– 2547 =. 2+5+4+7 = 18 .., so yes , 2547 is divisible by 3 cuz it's the multiple of 3

––– 5628 =. 5+6+4+8 = 23 .., no it's not divisible by 3

––– 10674 = 1+0+6+7+4 = 18 .., yes ,it's is divisible by 3

_______divisibility of 4 = last two digit should be multiple of 4

___ 30451 = no .., it's not

___2546 = no ., it's not

___5648 = yes ..,it's divisible by 4 cuz 48 is the multiple of 4

___10674= no .., its not

_______ divisibility of 5 = no should have 0 and 5 at last ...,

___30451 = no it's not

___2547 = no.its not

___5648 = no it's not

___10674 = no it's not

_______ divisibility of 9 = all no. when added should be multiple of 9

___30451 = no it's not

___2547 = yes . it's is divisible by 9 cuz when we add all no .., we get 18 which is multiple of 9

___5648 = no it's not

___10674 = yes .,it's is divisible by 9 cuz by adding all these we get 18 and 18 is multiple of 9

MARK ME AS BRANIEST ILL GIVE U 10 THNXX