using divisibility test which of the following numbers are divisible by 11 a) 5335 b) 9020813
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For the first part it is divisible.
for the second part it is not divisible.
the divisibility test for 11 is take the sum of all digits at even places and at odd places and subtract them. if the difference is divisible by 11 then the number is divisible by 11. otherwise it is not.
so for the first part the number is 5335.
so the sum of all digits at even places is equal to 5 + 3 which is equal to 8.
the sum of all digits at odd places is 3 + 5 which is 8.
8 - 8=0 which is divisible by 11 has zero x 11 is zero.
for second number the sum of all digits at odd places is 3 + 8 + 2 + 9 which gives out to be 22.
sum of digits at even places is equal to 0 + 0 + 1 which is 1
22 - 1 is 21 which is not divisible by 11 hence the number 9 million 20 thousand 813 is not divisible by 11
for the second part it is not divisible.
the divisibility test for 11 is take the sum of all digits at even places and at odd places and subtract them. if the difference is divisible by 11 then the number is divisible by 11. otherwise it is not.
so for the first part the number is 5335.
so the sum of all digits at even places is equal to 5 + 3 which is equal to 8.
the sum of all digits at odd places is 3 + 5 which is 8.
8 - 8=0 which is divisible by 11 has zero x 11 is zero.
for second number the sum of all digits at odd places is 3 + 8 + 2 + 9 which gives out to be 22.
sum of digits at even places is equal to 0 + 0 + 1 which is 1
22 - 1 is 21 which is not divisible by 11 hence the number 9 million 20 thousand 813 is not divisible by 11
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