Question

Using divisibility test, write the smallest digit and the greatest digit in the blank space of __4321, so that the number formed is divided by 3. Also, mention​

Answer 1

Step-by-step explanation:

We know that the divisibility of 3 is the sum of the digits which is divisible by 3

just like your question,

let the blank space be x

x +4+3+2+1= x +10

Now, we have to think that what is smallest or gratest no. which should be take the place of x. and divisible by Theni.3

So, the multiples of 3 : 3,6,9,12,15,18,21,24,27,30...

so the suitable no. is 2 , 5, 8.. and many more which makes the digits divisible by 3

For the suitable value of x= 2 : 2+4+3+2+1=12 which is divisible by 3

so, the digits are 24321

For the suitable value of x = 5 :

5+4+3+2+1 = 15 which is divisible by 3

so, the digits are 54321

For the suitable value of x = 8

8+4+3+2+1=18 which is divisible by 3

so the digits are 84321

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