Question

using division algorithm, find the quotient and remainder on dividing f(x) by g(x) whose f(x)=6x3+13x2+x-2 and g(x)=2x+1

Answer 1

r (x)=0.........................

Answer 2

Answer:

The remainder is  0 and Quotient is $3x^2+5x-2$

Step-by-step explanation:

Dividend =$6x^3+13x^2+x-2$

Divisor = $2x+1$

$Dividend = (Divisor \times Quotient)+Remainder$

$6x^3+13x^2+x-2= (2x+1 \times 3x^2)+(10x^2+x-2)$

$6x^3+13x^2+x-2= (2x+1 \times 3x^2+5x)+(-4x-2)$

$6x^3+13x^2+x-2= (2x+1 \times 3x^2+5x-2)+(0)$

Thus the remainder is 0

Quotient = $3x^2+5x-2$

Hence the remainder is  0 and Quotient is $3x^2+5x-2$