using division algorithm if 4x3+7x2-4x+k is completely divisible by x2-1, find the value of k
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Hi ,
( 4x³ + 7x² - 4x + k ) ÷ x² - 1
x² - 1 ) 4x³ + 7x² - 4x + k ( 4x + 7
4x³ + 0 - 4x
__________________
7x² + k
7x² - 7
_________________
k + 7
It is completly divisible
Therefore ,
remainder = 0
k + 7 = 0
k = - 7
I hope this helps you.
:)
( 4x³ + 7x² - 4x + k ) ÷ x² - 1
x² - 1 ) 4x³ + 7x² - 4x + k ( 4x + 7
4x³ + 0 - 4x
__________________
7x² + k
7x² - 7
_________________
k + 7
It is completly divisible
Therefore ,
remainder = 0
k + 7 = 0
k = - 7
I hope this helps you.
:)
mysticd:
:)
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