Question

Using division show that x²+1 is factor of x⁶-x⁵-x⁴+3x³+4x²+4x+6

Answer 1

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Answer 2

Answer:

( x² + 1 ) IS A FACTOR OF ( x^6 - x^5 - x^4 + 3x³ + 4x² + 4x + 6 )

Step-by-step explanation:

x^4 - x³ - 2x² + 4x + 6

____________________________

x² + 0x + 1 ) x^6 - x^5 - x^4 + 3x³ + 4x² + 4x + 6

(-) x^6 + 0x^5 + x^4

(-) (-) (-)

______________

- x^5 - 2x^4 + 3x³

(-) - x^5 - 0x^4 - x³

(+) (+) (+)

_____________

- 2x^4 + 4x³ + 4x²

(-) - 2x^4 - 0x³ - 2x²

(+) (+) (+)

_______________

4x³ + 6x² + 4x

(-) 4x³ + 0x² + 4x

(-) (-) (-)

______________

6x² + 0x + 6

(-) 6x² + 0x + 6

(-) (-) (-)

_____________

0x² + 0x - 0

_____________

( x² + 1 ) IS A FACTOR OF ( x^6 - x^5 - x^4 + 3x³ + 4x² + 4x + 6 )

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