using ecuild division algorithm find hcf of 726 and 275
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a=726
b=275
a=bq+r
726=275×2+176
here r=not0
again a=275
b=176
275=176×1+99
176=99×1+77
99=77×1+22
77=22×3+11
22=11×2+0
here's r=0
hcf=11
b=275
a=bq+r
726=275×2+176
here r=not0
again a=275
b=176
275=176×1+99
176=99×1+77
99=77×1+22
77=22×3+11
22=11×2+0
here's r=0
hcf=11
swara960:
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