Question

Using edl find hcf of 506 and 155

Answer 1

Step-by-step explanation:

a=bq+r

a=506,b=155

506=155*465+41

155=41*3+32

41=32*1+9

32=9*3+5

9=5*1+4

5=4*1+1

4=1*4+0

Therefore H.C.F. Of 506 and 155 is 1