Math, asked by Anthony2008, 1 day ago

Using either the elimination method or the substitution method, solve the following pairs of simultaneous equations.

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Answers

Answered by Aindvi
0

Answer:

14x + 6y = 9 ____ (1)

6x - 15y = -2 ____ (2)

Using Substitution method.

From (1)

14x + 6y = 9

6y = 9 - 14x

y = 9-14x/ 6

Now From (2)

6x - 15y = -2

6x - 15 ( 9-14x/6 ) = -2

6x + (-135+210x)/6 = -2

6x - 135 + 210x = -2 × 6

216x - 135 = -12

216x = -12 + 135

216x = 123

x = 123/216

x = 41/72

From (1)

14x + 6y = 9

14 × 41/72 + 6y = 9

287/36 + 6y = 9

6y = (9×36)/287

y = (9×36)/(287×6)

y = 54/287

The values are:

x = 41/72

y = 54/287

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