Using elementary transformations, find the inverse of the matrix ( 1 3 −2 3 0 −1 2 1 0 )
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Answered by
1
Using elementary transformations, find the inverse of the matrix ( 1 3 −2 3 0 −1 2 1 0 )
Answered by
5
Step-by-step explanation:
Given: −3(x−7)≥15−7x>
3
x+1
−3x+21≥15−7x>
3
x+1
⇒−3x+21≥15−7x and 155−7x>
3
x+1
⇒4x≥−6 and 45−21x>x+1
⇒x≥−
2
3
and 44>22x
⇒x≥
2
−3
and 2>x
∴ Solution set ={x:x∈R,
2
−3
≤x<2}
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