Question

using elimination method solve 2x -y=1 and 5x + 2y =25​

Answer 1

Given:-

$\bf 2x-y=1 ...(1)$

$\bf 5x+2y=25 ...(2)$

To Find:-

Solve the equation by elimination method

Solution:-

Multiplying eq(1) by 2.

$\bf 2[2x-y=1] \longrightarrow 4x-2y=2 ...(3)$

Adding eq (3) and eq(1).

$\bf \: \:4x-2y=2$

$\bf + \:5x+2y=25$

$\bf 9x \:\:=27$

$\bf 9x=27$

$\bf x= \frac{27}{9}$

$\bf x=3 ...(4)$

Substituting eq(4) in eq(2)

$\bf 5(3)+2y=25$

$\bf 15+2y=25$

$\bf 2y=10$

$\bf y= \frac{10}{2}$

$\bf y=5$

$\bf\red{ x=3 \:\: and \:\: y=5}$

Answer 2

Answer:

I hope it's helpful for you to the answer to

Step-by-step explanation:

2x−y=1...(1)

5

�

+

2

�

=

25...

(

2

)

5x+2y=25...(2)

To Find:-

Solve the equation by elimination method

Solution:-

Multiplying eq(1) by 2.

2

[

2

�

−

�

=

1

]

⟶

4

�

−

2

�

=

2...

(

3

)

2[2x−y=1]⟶4x−2y=2...(3)

Adding eq (3) and eq(1).

4

�

−

2

�

=

2

4x−2y=2

+

5

�

+

2

�

=

25

+5x+2y=25

9

�

=

27

9x=27

9

�

=

27

9x=27

�

=

27

9

x=

9

27

�

=

3...

(

4

)

x=3...(4)

Substituting eq(4) in eq(2)

5

(

3

)

+

2

�

=

25

5(3)+2y=25

15

+

2

�

=

25

15+2y=25

2

�

=

10

2y=10

�

=

10

2

y=

2

10

�

=

5

y=5

�

=

3

�

�

�

�

=

5

x=3andy=5