Using elimination method, solve 8y-5z=7, 3y=4(z-2)
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Answer:
z=5,y=4
Step-by-step explanation:
8y-5z=7·······eqn(1)
3y=4(z-2)⇒3y-4z=-8......eqn(2)
24y-15z=21.......(multiplying eqn.1 by 3)....I
24y-32z=-64........(multiplying eqn.2 by 8.....II
after subtracting II from I we have 17z=85⇒z=5
substituing z=5 in eqn (1) we have y=4.
hence solved.
hope this helps.
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