Question

using equipartition of energy calculate specific heat of diatomic gas​

Answer 1

Explanation:

Do State Law of equipartition of energy use this law to calculate specific heats of monoatomic diatomic and triatomic gases

Answer 2

Answer:

The Law of equipartition of energy states that for a dynamical system in thermal equilibrium the total energy of the system is shared equally by all the degrees of freedom. The energy associated with each degree of freedom per molecule is 21kT, where k is the Boltzmann’s constant.

For example, for a monoatomic molecule, each molecule has 3 degrees of freedom. According to the kinetic theory of gases, the mean kinetic energy of a molecule is 23kT.

Specific heat capacity of Monatomic gas:

The molecules of a monatomic gas have 3 degrees of freedom.

The average energy of a molecule at temperature T is 23KBT

The total internal energy of a mole is: 23KBT×NA

The molar specific heat at constant volume Cv is

For an ideal gas,

Cv (monatomic gas) =dTdU=23RT

For an ideal gas, Cp−Cv=R

where Cp is molar specific heat at constant pressure.

Thus, Cp=25R

Specific heat capacity of Diatomic gas:

The molecules of a monatomic gas have 5 degrees of freedom, 3 translational, and 2 rotational.

The average energy of a molecule at temperature T is 25KBT

The total internal energy of a mole is: 25KBT×NA

The molar specific heat at constant volume Cv is

For an ideal gas,

Cv (monatomic gas) =dTdU=25RT

For an ideal gas, C