Question

using Euclid division algorithm find HCF of 408,128​

Answer 1

Answer:

408=128×3+24

128=24×7+0

THE HCF is 24

Answer 2

8 is the value of HCF of 408 and 128.

Step-by-step explanation:

Since we have given that

408 and 128

We need to find the HCF using Euclid division.

$a=bq+r,\ 0\leq r\leq b$

We will repeat the steps until our 'r' becomes 0.

So, it becomes,

$408=128\times 3+24\\\\128=24\times 5+8\\\\24=8\times 3+0$

Hence, 8 is the value of HCF of 408 and 128.

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