Question

Using Euclid division algorithm find HCF of 900 and 270

Answer 1

Answer:

Let a and b be any two positive

integers .Then there exists two

unique whole numbers q and r

such that

a = bq + r ,

0 ≤ r < b

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Now ,

900 and 270 , start with the larger

integer , that is 900. Apply the

Division lemma , we get

900 = 270 × 3 + 90

270 = 90 × 3 + 0

The remainder has now become

zero . Now our procedure stops.

Since the divisor at this stage is 90.

Therefore ,

HCF ( 900 , 270 ) = 90

I hope this helps you.

Step-by-step explanation:

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