using euclid division algorithm ,find the HCF of 2160 and 3520
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7
a=bq+r
a=3520,b=2160
3520=2160×1+1360
a=2160,b=1360
2160=1360×1+800
a=1360,b=800
1360=800×1+560
a=800,b=560
800=560×1+240
a=560,b=240
560=240×2+80
a=240,b=80
240=80×3+0
hence, H.C.F.=80....
a=3520,b=2160
3520=2160×1+1360
a=2160,b=1360
2160=1360×1+800
a=1360,b=800
1360=800×1+560
a=800,b=560
800=560×1+240
a=560,b=240
560=240×2+80
a=240,b=80
240=80×3+0
hence, H.C.F.=80....
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Answered by
5
HCF=80
Hope this is Helpful...
Hope this is Helpful...
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