Using euclid division algorithm to find hcf of 960 and 1575
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Hi,
Euclid's division algorithm:
Given positive integers a and b , there
exist whole numbers q and r satisfying
a = bq + r , 0 < r < b
_
According to the problem given ,
Applying Ecuclid's division lemma to 960,
and 1575, we get
1575 = 960 × 1
960 = 615 ×1 + 270
615 = 270 × 1 + 75
270 = 75 × 3 + 45
75 = 45 × 1 + 30
45 = 30 × 1 + 15
30 = 15 × 2 + 0
Notice that the remainder has become zero,
and we cannot proceed anybfurther.
We claim that the HCF of 960 and 1575 is the
divisor at this stage , i.e . 15.
Mark it as brainliest if its helpful.Hope it helps.
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