using Euclid division lema find hcf of 867 and 253
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As, 867=255 × 3 +102
255 = 102 × 2 + 51
102 = 51 × 2 + 0
So, HCF (867,255) = 51
255 = 102 × 2 + 51
102 = 51 × 2 + 0
So, HCF (867,255) = 51
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Solution :-
H.C.F. of 867 and 255
Using Euclid's division lemma
867 = 3 × 255+ 102
Since, remainder 102 is not equal to 0, we apply the division lemma to 255 and 102
255 = 2 × 102 + 51
102 = 2 × 51 + 0
Now, the remainder is 0
So, H.C.F. of 867 and 255 is 51
Answer.
H.C.F. of 867 and 255
Using Euclid's division lemma
867 = 3 × 255+ 102
Since, remainder 102 is not equal to 0, we apply the division lemma to 255 and 102
255 = 2 × 102 + 51
102 = 2 × 51 + 0
Now, the remainder is 0
So, H.C.F. of 867 and 255 is 51
Answer.
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