using Euclid division lemma, find the hcf of 714 and 924
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Answered by
16
924=714*1+210
714=210*3+84
210=84*2+ 42
84=42*2+0
hcf of 924 nd 714 is 42
714=210*3+84
210=84*2+ 42
84=42*2+0
hcf of 924 nd 714 is 42
durgasivani:
sry i did wrong
Answered by
10
924 > 714
By Euclid's division lemme
a = bq + r
924 = 714 ×1 +210
here r is not equals to Zero, then
714 = 210 × 3 + 84
Here r is not equals to Zero, then
210 = 84 × 2 + 42
here r is not equals to Zero, then
84 = 42 ×2 + 0
here r = 0
Then HCF Of 714 and 924 is 42.
By Euclid's division lemme
a = bq + r
924 = 714 ×1 +210
here r is not equals to Zero, then
714 = 210 × 3 + 84
Here r is not equals to Zero, then
210 = 84 × 2 + 42
here r is not equals to Zero, then
84 = 42 ×2 + 0
here r = 0
Then HCF Of 714 and 924 is 42.
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