Question

Using Euclid's algorithm, find the HCF of 240 and 228.​

Answer 1

The H.C.F. of ‘240 and 228’ by “Euclid division algorithm” is 12.

To find:

H.C.F. of 240 and 228

Solution:

Here 240 > 228 we always divide greater number with smaller one.

Divide 240 by 228 we get 1 quotient and 12 as remainder so that

240=228 \times 1+12240=228×1+12

Divide 228 by 12 we get 19 quotient and there is ‘no remainder’ so we can write

228=12 \times 19+0228=12×19+0

As there are no remainder, 12 is the “H.C.F. of 240 and 228”.

Answer 2

Answer:

240=228*1+12

228=12*19+0

Step-by-step explanation:

Hope it will help you