using Euclid's algorithmi find HCF of 240 and 228.
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70
Euclid's algorithm,
a= bq + r
where, 0 ≤ r < b
So,
240= 228 x 1 + 12 ( r ≠ 0 )
228= 12 x 19 +0. ( r =0 )
So,
HCF ( 240,228) = 12
a= bq + r
where, 0 ≤ r < b
So,
240= 228 x 1 + 12 ( r ≠ 0 )
228= 12 x 19 +0. ( r =0 )
So,
HCF ( 240,228) = 12
Answered by
3
Answer: HCF is 5
Step-by-step explanation:
288 = 240 × 1 + 48 ; Rnot =0
240 = 48 × 5 + 0 ; R=0
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