Question

using Euclid's division algorithm find the HCF of 1305,1365,1530​

Answer 1

Step-by-step explanation:

HCF of 1305 and 1365 : 1365 = 1305*1 + 60 1305 = 60*21 + 45 60 = 45*1 + 15 45 = 15*3 + 0

So HCF of 1305 and 1365 is 15 Next find HCF of 15 and 1530 : 1530 = 15*102 + 0 So HCF of 15 and 1530 is 15 Thu

s the HCF of 1305, 1365 and 1530 is 15.

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