USING EUCLID'S DIVISION ALGORITHM, FIND THE HCF OF 441, 567 AND 693.
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Hey Mate !!!!!! Here's Your Answer
Let us find the H.C.F of two numbers 441, 567
567 = 441 × 1 + 126
=> 441 = 126 × 3 + 63
=> 126 = 63 × 2 + 0
H.C.F of (567,441) = 63
Now let us find the H.C.F of 693 and 63
=> 693 = 63 × 11 + 0
H.C.F (693,63) = 63
From both of H.C.F
We can write :-
H.C.F (441, 567, 693) = 63
Hope This Helps !!!!!!!!!!!
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