Using Euclid's division algorithm ,find the largest number that divides 1251,9377,and 15628 leaving remainders 1,2&3
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find the largest number that divides 1251,9377,and 15628 leaving remainders 1,2 & 3
1251 leaves remainder 1
=> 1251-1 = 1250
9377 leaves remainder 2
=> 9377-2 = 9375
15628 leaves remainder 3
=> 15628-3 = 15625
The largest number that divides 1251,9377,and 15628 leaving remainders 1,2 & 3 will be the HCF of 1250,9375 and 15625
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Finding HCF using Euclid division lemma:-
a = bq + r
0 ≤ r < b
a > b
First,find the HCF of 15625 and 9375
15625 = 9375 × 1 + 6250
⟹ 9375 = 6250 × 1 + 3125
⟹ 6250 = 3125 × 2 + 0
remainder(r) = 0
∴ HCF (15625 and 9375) = 3125
Now,find the HCF of 3125 and 1250
3125 = 1250 × 2 + 625
1250 = 625 × 2 + 0
remainder(r) = 0
∴ HCF (3125 and 1250) = 625
The largest number that divides 1251,9377,and 15628 leaving remainders 1,2 & 3 is 625.
Hope it helps
1251 leaves remainder 1
=> 1251-1 = 1250
9377 leaves remainder 2
=> 9377-2 = 9375
15628 leaves remainder 3
=> 15628-3 = 15625
The largest number that divides 1251,9377,and 15628 leaving remainders 1,2 & 3 will be the HCF of 1250,9375 and 15625
====================
Finding HCF using Euclid division lemma:-
a = bq + r
0 ≤ r < b
a > b
First,find the HCF of 15625 and 9375
15625 = 9375 × 1 + 6250
⟹ 9375 = 6250 × 1 + 3125
⟹ 6250 = 3125 × 2 + 0
remainder(r) = 0
∴ HCF (15625 and 9375) = 3125
Now,find the HCF of 3125 and 1250
3125 = 1250 × 2 + 625
1250 = 625 × 2 + 0
remainder(r) = 0
∴ HCF (3125 and 1250) = 625
The largest number that divides 1251,9377,and 15628 leaving remainders 1,2 & 3 is 625.
Hope it helps
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