using euclid's division find HCF of 210 and 55
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210=55*3 + 45
55 = 45*1 + 10
45 = 10*4 + 5
10 = 5*2 + 0
Hence the HCF of 210 and 55 is "5"
55 = 45*1 + 10
45 = 10*4 + 5
10 = 5*2 + 0
Hence the HCF of 210 and 55 is "5"
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