Question

. Using
Euclid's division
HCF of
441, 567
algorithm find
and 693.
maths std 10
,pls its urgent​

Answer 1

Answer:

pls follow

Step-by-step explanation:

Step 1 ⇒ 567 = 441 × 1 + 126.

Step 2 ⇒ 441 = 126 × 3 + 63.

Step 3 ⇒ 126 = 63 × 2 + 0.

Step 1 ⇒ 693 = 63 × 11 + 0.

Answer 2

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