Using Euclid’s Division lemma, find HCF of 130 and 510
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Answer:
510 > 130
so 510 = 130 × 3 + 120
r is not equal to 0
so we will continue this step again
130 = 120 × 1 + 10
again r is not equal to zero
so we will again continue
120 = 10 × 12 + 0
since r = 0
HCF = 10
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