Using Euclid's Division Lemma find out the HCF of 420,130
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Euclid's Division Lemma =
a = bq + r
Given Numbers = 420,130
Finding HCF (Highest Common Factor) :
420= 130×3+30
130=30×4+10
30=10×3+0
The required HCF is = 10.
Thus when we divided 30 by 10 , the remainder we get is 0.
a = bq + r
Given Numbers = 420,130
Finding HCF (Highest Common Factor) :
420= 130×3+30
130=30×4+10
30=10×3+0
The required HCF is = 10.
Thus when we divided 30 by 10 , the remainder we get is 0.
kuldeepkauraujla1976:
hlo
Answered by
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hey mate here is your answer ✌♥✌♥✌
Euclid's division lemma is
a=bq+r
HCF (420,130)=?
now here 420>130
so by applying Euclid's division lemma
420=130×3+30
here r=30
so 130=30×4+10
here r=10
so 30=10×3+0
here r=0
so HCF (420,130)=10
hope it will be helpful to you
mark me brainliest ✌✌✌✌✌
Euclid's division lemma is
a=bq+r
HCF (420,130)=?
now here 420>130
so by applying Euclid's division lemma
420=130×3+30
here r=30
so 130=30×4+10
here r=10
so 30=10×3+0
here r=0
so HCF (420,130)=10
hope it will be helpful to you
mark me brainliest ✌✌✌✌✌
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