Math, asked by awsanket9186, 1 year ago

Using euclid's division Lemma find the HCF of 441 567 693

Answers

Answered by tejasmba
918
Solution -

Euclid's division Lemma (algorithm) to fine HCF of (441, 567, 693)

Consider a = 693    b = 567  and   c = 441

By Euclid's division lemma,

a = bq + r        (as dividend = divisor * quotient + remainder)

First consider two numbers a = 693 and b = 567

693 = 567 * 1 + 126               (r not equals to 0)

567 = 126 * 4 + 63                  (r not equals to 0)

126 = 63 * 2 + 0                      ( r is equal to 0)

Stop here.

HCF of 693, 567 = 63.

Now find HCF of (441, 63)

where c = 441 and assume d = 63

Again apply Euclid's division lemma 

c = dq + r

441 = 63 * 7 + 0                (r is equal to 0)

Therefore, HCF of 441 and 63 is 63.

Therefore, HCF of 441, 567 and 693 is 63.
Answered by Anonymous
357

Let us find the HCF of two numbers 441, 567


Using Euclid divisions algorithm


Step 1 => 567 = 441 × 1 + 126


Step 2 => 441 = 126 × 3 + 63


Step 3 => 126 = 63 × 2 + 0


HCF of (567,441) = 63


Now let us find the HCF of 693 and 63


Step 1 => 693 = 63 × 11 + 0


HCF (693,63) = 63


From both of HCF


We can write :-


HCF(441,567,693) = 63

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