Using euclid's division Lemma find the HCF of 441 567 693
Answers
Answered by
918
Solution -
Euclid's division Lemma (algorithm) to fine HCF of (441, 567, 693)
Consider a = 693 b = 567 and c = 441
By Euclid's division lemma,
a = bq + r (as dividend = divisor * quotient + remainder)
First consider two numbers a = 693 and b = 567
693 = 567 * 1 + 126 (r not equals to 0)
567 = 126 * 4 + 63 (r not equals to 0)
126 = 63 * 2 + 0 ( r is equal to 0)
Stop here.
HCF of 693, 567 = 63.
Now find HCF of (441, 63)
where c = 441 and assume d = 63
Again apply Euclid's division lemma
c = dq + r
441 = 63 * 7 + 0 (r is equal to 0)
Therefore, HCF of 441 and 63 is 63.
Therefore, HCF of 441, 567 and 693 is 63.
Euclid's division Lemma (algorithm) to fine HCF of (441, 567, 693)
Consider a = 693 b = 567 and c = 441
By Euclid's division lemma,
a = bq + r (as dividend = divisor * quotient + remainder)
First consider two numbers a = 693 and b = 567
693 = 567 * 1 + 126 (r not equals to 0)
567 = 126 * 4 + 63 (r not equals to 0)
126 = 63 * 2 + 0 ( r is equal to 0)
Stop here.
HCF of 693, 567 = 63.
Now find HCF of (441, 63)
where c = 441 and assume d = 63
Again apply Euclid's division lemma
c = dq + r
441 = 63 * 7 + 0 (r is equal to 0)
Therefore, HCF of 441 and 63 is 63.
Therefore, HCF of 441, 567 and 693 is 63.
Answered by
357
Let us find the HCF of two numbers 441, 567
Using Euclid divisions algorithm
Step 1 => 567 = 441 × 1 + 126
Step 2 => 441 = 126 × 3 + 63
Step 3 => 126 = 63 × 2 + 0
HCF of (567,441) = 63
Now let us find the HCF of 693 and 63
Step 1 => 693 = 63 × 11 + 0
HCF (693,63) = 63
From both of HCF
We can write :-
HCF(441,567,693) = 63
Similar questions